Which of the following alcohols is not presen | vedclass

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(A) The reaction of an ether with $H_3O^+$ (acid-catalyzed cleavage) typically follows an $S_N2$ mechanism for primary and secondary alkyl groups. In

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(A) The reaction of an ether with $H_3O^+$ (acid-catalyzed cleavage) typically follows an $S_N2$ mechanism for primary and secondary alkyl groups. In the given ether,both alkyl groups attached to the oxygen are secondary. Cleavage occurs at the $C-O$ bond,resulting in the formation of two alcohols. Since the reaction proceeds via an $S_N2$ mechanism,the configuration at the chiral center where the bond is broken will be inverted. For the left side $(CH(Me)(D)-O-)$,the $C-O$ bond cleavage leads to $CH(Me)(D)OH$ with inversion. For the right side $(-O-CH(Me)(Et))$,the $C-O$ bond cleavage leads to $CH(Me)(Et)OH$ with inversion. Option $A$ represents the alcohol from the left side without inversion. Option $B$ represents the alcohol from the right side without inversion. Option $C$ represents the alcohol from the left side with inversion. Option $D$ represents the alcohol from the right side with inversion. Since the reaction involves $S_N2$ inversion,the products formed are the inverted alcohols. Therefore,the alcohols with the original configuration (non-inverted) are not present in the major product mixture.

Which of the following alcohols is not present in the mixture containing major products of the reaction shown below?

Similar Questions

Identify $A$ and $B$ in the following reaction: $C_6H_5CH_2-O-C_6H_5 + HI \rightarrow A + B$

Identify the product $(A)$ of the following reaction:
$C_2H_5-O-C_2H_5 + CO \xrightarrow[500 \text{ atm}]{BF_3 / 150^{\circ}C} A$

The acidic hydrolysis of ether $(X)$ shown below is fastest when :

The ether $C_6H_5-O-CH_2-C_6H_5$ when treated with $HI$ produces:

The reaction given below is known as:
$C_2H_5ONa + IC_2H_5 \xrightarrow{} C_2H_5OC_2H_5 + NaI$

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